DGCA Air Navigation: Psr / Pet Questions
186 exam-style Psr / Pet questions for the DGCA Air Navigationpaper (CPL & ATPL). The first 12 are free below with answers and explanations — sign up free to practise all of them with progress tracking.
- Q1
What is the distance to the point of safe endurance if an aircraft has a TAS of 300 knots and a safe endurance of 10 hours, if the wind component on the outbound leg is 50 knots headwind?
- A1458 nm.
- B1505 nm.
- C1554 nm.
- D1625 nm.
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Correct answer: A. 1458 nm.
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- Q2
What is the time to the point of safe return (PSR) if the distance from A to B is 2368 nautical miles, the outbound groundspeed in 365 knots, the homebound groundspeed is 480 knots, and safe endurance is 8 hours 30 minutes?
- A190 min.
- B209 min.
- C219 min.
- D290 min.
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Correct answer: D. 290 min.
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- Q3
What is the distance from 'Q' to the Point of Safe Return (PSR) for an aircraft that was over 'Q' at 1320 hours flying direct to 'R' given the following data? Distance 'Q' to 'R' 3016 nm, True airspeed 480 kt, Safe endurance 10 Hours, if the mean wind component 'outbound' - 90 kt, and the mean wind component 'homebound' is +75 kt.
- A1320 nm.
- B1530 nm.
- C2290 nm.
- D2375 nm.
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Correct answer: C. 2290 nm.
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- Q4
What is the distance to B from the equal-time-point given the following data? Distance A to B is 360 nm Wind component A - B is -15kt TAS is 180 kt. Wind component B-A is +15 kt.
- A165 nm.
- B170 nm.
- C175 nm.
- D180 nm.
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Correct answer: A. 165 nm.
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- Q5
An aircraft is flying at a TAS of 300 knots over a stretch of water between 2 airfields 500 nm apart. What is the distance from the first airfield to the equal time point (ETP) if the wind component is 60 knots head?
- A200 nm.
- B250 nm.
- C280 nm.
- D300 nm.
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Correct answer: D. 300 nm.
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- Q6
How far can the aeroplane fly out from its base and return in one hour, when flying at TAS 180 kt on a track of 090°, if the W/V is 045°/50kt?
- A58 nm.
- B85 nm.
- C88 nm.
- D175 nm.
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Correct answer: B. 85 nm.
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- Q7
For a distance of 1860 NM between Q and R, a ground speed "out" of 385 kt, a ground speed "back" of 465 kt and an endurance of 8 HR (excluding reserves) the distance from Q to the point of safe return (PSR) is?
- A1685 NM.
- B1532 NM.
- C930 NM.
- D1865 NM.
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Correct answer: A. 1685 NM.
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- Q8
Two points A and B are 1000 NM apart. TAS =490 kt. On the flight between A and B the equivalent headwind is-20 kt. On the return leg between B and A, the equivalent headwind is +40kt. What distance from A, along the route A to B, is the Point of Equal Time (PET)?
- A470 NM.
- B455 NM.
- C500 NM.
- D530 NM.
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Correct answer: D. 530 NM.
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- Q9
An aeroplane is flying at TAS 180 kt on a track of 090°. The W/V is 045°/50kt. How far can the aeroplane fly out from its base and return in one hour?
- A85 NM.
- B88 NM.
- C56 NM.
- D176 NM.
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Correct answer: A. 85 NM.
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- Q10
An aircraft with 180 minutes approval for ETOPS, must be :
- Ano more than 90 minutes from a suitable alternate, and 90 minutes from departure, at the one engine inoperative TAS
- Bno more than 180 minutes from a suitable alternate, in still air, at the all engine TAS.
- Cno more than 180 minutes from a suitable alternate, in still air, at the one engine inoperative TAS.
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Correct answer: C. no more than 180 minutes from a suitable alternate, in still air, at the one engine inoperative TAS.
An ETOPS approval of 180 minutes means the aeroplane may operate up to 180 minutes from a suitable alternate, measured in still air at the one-engine-inoperative cruise speed, not the all-engine speed.
- Q11
Given: Distance 'A' to 'B' 2346 NM, Groundspeed 'out' 365 kt, Groundspeed 'back' 480 kt. The time from 'A' to the Point of Equal Time (PET) between 'A' and 'B' is?
- A167 MIN.
- B219 MIN.
- C290 MIN.
- D197 MIN.
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Correct answer: B. 219 MIN.
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- Q12
ETOPS flight is a twin engine jet aeroplane flight conducted over a route, where no suitable airport is within an area of:
- A75 minutes flying time at the approved one engine out cruise speed
- B60 minutes flying time in still air at the approved one engine out cruise speed.
- C30 minutes flying time at the normal cruising speed.
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Correct answer: B. 60 minutes flying time in still air at the approved one engine out cruise speed.
An ETOPS operation is a twin-engine flight over a route where no suitable airport lies within 60 minutes flying time, calculated in still air at the approved one-engine-inoperative cruise speed.
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